(2x+1-x^2-7)=

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Solution for (2x+1-x^2-7)= equation:


Simplifying
(2x + 1 + -1x2 + -7) = 0

Reorder the terms:
(1 + -7 + 2x + -1x2) = 0

Combine like terms: 1 + -7 = -6
(-6 + 2x + -1x2) = 0

Remove parenthesis around (-6 + 2x + -1x2)
-6 + 2x + -1x2 = 0

Solving
-6 + 2x + -1x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
6 + -2x + x2 = 0

Move the constant term to the right:

Add '-6' to each side of the equation.
6 + -2x + -6 + x2 = 0 + -6

Reorder the terms:
6 + -6 + -2x + x2 = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -2x + x2 = 0 + -6
-2x + x2 = 0 + -6

Combine like terms: 0 + -6 = -6
-2x + x2 = -6

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -6 + 1

Reorder the terms:
1 + -2x + x2 = -6 + 1

Combine like terms: -6 + 1 = -5
1 + -2x + x2 = -5

Factor a perfect square on the left side:
(x + -1)(x + -1) = -5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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